4y+3(3y+6)=9y-1

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Solution for 4y+3(3y+6)=9y-1 equation: 



4y+3(3y+6)=9y-1

We move all terms to the left:

4y+3(3y+6)-(9y-1)=0

We multiply parentheses

4y+9y-(9y-1)+18=0

We get rid of parentheses

4y+9y-9y+1+18=0

We add all the numbers together, and all the variables

4y+19=0

We move all terms containing y to the left, all other terms to the right

4y=-19

y=-19/4

y=-4+3/4

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