-4+6(3b+2)=134

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Solution for -4+6(3b+2)=134 equation: 



-4+6(3b+2)=134

We move all terms to the left:

-4+6(3b+2)-(134)=0

We add all the numbers together, and all the variables

6(3b+2)-138=0

We multiply parentheses

18b+12-138=0

We add all the numbers together, and all the variables

18b-126=0

We move all terms containing b to the left, all other terms to the right

18b=126

b=126/18

b=7

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