-4*(x-2)*(x+5)-(-4x-1)*(x+3)=0

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Solution for -4*(x-2)*(x+5)-(-4x-1)*(x+3)=0 equation: 



-4(x-2)(x+5)-(-4x-1)(x+3)=0

We multiply parentheses ..

-4(+x^2+5x-2x-10)-(-4x-1)(x+3)=0

We multiply parentheses

-4x^2-20x+8x-(-4x-1)(x+3)+40=0

We multiply parentheses ..

-4x^2-(-4x^2-12x-1x-3)-20x+8x+40=0

We add all the numbers together, and all the variables

-4x^2-(-4x^2-12x-1x-3)-12x+40=0

We get rid of parentheses

-4x^2+4x^2+12x+1x-12x+3+40=0

We add all the numbers together, and all the variables

x+43=0

We move all terms containing x to the left, all other terms to the right

x=-43

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