(5-7)/x=(2(x+4))/x

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Solution for (5-7)/x=(2(x+4))/x equation: 



(5-7)/x=(2(x+4))/x

We move all terms to the left:

(5-7)/x-((2(x+4))/x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(-2)/x-((2(x+4))/x)=0

We calculate fractions


(-2)*x)/x^2+(-((2(x+4))*x)/x^2=0

We calculate fractions


((-2)*x)*x^2)/(x^2+(*x^2)+(-((2(x+4))*x)*x^2)/(x^2+(*x^2)=0



We calculate terms in parentheses: +(-((2(x+4))*x)*x^2)/(x^2+(*x^2), so:

-((2(x+4))*x)*x^2)/(x^2+(*x^2

We multiply all the terms by the denominator


-((2(x+4))*x)*x^2)+((*x^2)*(x^2

Back to the equation:

+(-((2(x+4))*x)*x^2)+((*x^2)*(x^2)



We get rid of parentheses

((-2)*x)*x^2)/(x^2+*x^2+(-((2(x+4))*x)*x^2)+((*x^2)*x^2=0

We multiply all the terms by the denominator


((-2)*x)*x^2)+(*x^2)*(x^2+((-((2(x+4))*x)*x^2))*(x^2+(((*x^2)*x^2)*(x^2=0

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