-4(y+3)2y=24

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Solution for -4(y+3)2y=24 equation: 



-4(y+3)2y=24

We move all terms to the left:

-4(y+3)2y-(24)=0

We multiply parentheses

-8y^2-24y-24=0

a = -8; b = -24; c = -24;
Δ = b2-4ac
Δ = -242-4·(-8)·(-24)
Δ = -192
Delta is less than zero, so there is no solution for the equation

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