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(1)/(2)(3x-2)-(1)/(3)(x+2)=4
We move all terms to the left:
(1)/(2)(3x-2)-(1)/(3)(x+2)-(4)=0
Domain of the equation: 2(3x-2)!=0
x∈R
Domain of the equation: 3(x+2)!=0We calculate fractions
x∈R
(3xx/(2(3x-2)*3(x+2))+(-2x3/(2(3x-2)*3(x+2))-4=0
We can not solve this equation
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