-4(x-4)+2x=3(x-3)-3

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Solution for -4(x-4)+2x=3(x-3)-3 equation: 



-4(x-4)+2x=3(x-3)-3

We move all terms to the left:

-4(x-4)+2x-(3(x-3)-3)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(3(x-3)-3)=0

We multiply parentheses

2x-4x-(3(x-3)-3)+16=0



We calculate terms in parentheses: -(3(x-3)-3), so:

3(x-3)-3

We multiply parentheses

3x-9-3

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

-2x-(3x-12)+16=0

We get rid of parentheses

-2x-3x+12+16=0

We add all the numbers together, and all the variables

-5x+28=0

We move all terms containing x to the left, all other terms to the right

-5x=-28

x=-28/-5

x=5+3/5

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