4m2-27m=40

Solution for 4m2-27m=40 equation:

4m^2-27m=40

We move all terms to the left:

4m^2-27m-(40)=0

a = 4; b = -27; c = -40;
Δ = b2-4ac
Δ = -272-4·4·(-40)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-37}{2*4}=\frac{-10}{8}
=-1+1/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+37}{2*4}=\frac{64}{8}
=8
$