-4(v+2)=3v-9+3(v+1)

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Solution for -4(v+2)=3v-9+3(v+1) equation: 



-4(v+2)=3v-9+3(v+1)

We move all terms to the left:

-4(v+2)-(3v-9+3(v+1))=0

We multiply parentheses

-4v-(3v-9+3(v+1))-8=0



We calculate terms in parentheses: -(3v-9+3(v+1)), so:

3v-9+3(v+1)

determiningTheFunctionDomain
3v+3(v+1)-9

We multiply parentheses

3v+3v+3-9

We add all the numbers together, and all the variables

6v-6

Back to the equation:

-(6v-6)



We get rid of parentheses

-4v-6v+6-8=0

We add all the numbers together, and all the variables

-10v-2=0

We move all terms containing v to the left, all other terms to the right

-10v=2

v=2/-10

v=-1/5

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