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1/5(10x-25)=4x-5-2x
We move all terms to the left:
1/5(10x-25)-(4x-5-2x)=0
Domain of the equation: 5(10x-25)!=0We add all the numbers together, and all the variables
x∈R
1/5(10x-25)-(2x-5)=0
We get rid of parentheses
1/5(10x-25)-2x+5=0
We multiply all the terms by the denominator
-2x*5(10x-25)+5*5(10x-25)+1=0
Wy multiply elements
-10x^2(1+25x(1+1=0
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