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-4(v+2)=3v-9+3(3v+1)
We move all terms to the left:
-4(v+2)-(3v-9+3(3v+1))=0
We multiply parentheses
-4v-(3v-9+3(3v+1))-8=0
We calculate terms in parentheses: -(3v-9+3(3v+1)), so:We get rid of parentheses
3v-9+3(3v+1)
determiningTheFunctionDomain 3v+3(3v+1)-9
We multiply parentheses
3v+9v+3-9
We add all the numbers together, and all the variables
12v-6
Back to the equation:
-(12v-6)
-4v-12v+6-8=0
We add all the numbers together, and all the variables
-16v-2=0
We move all terms containing v to the left, all other terms to the right
-16v=2
v=2/-16
v=-1/8
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