(n+3)/5=(-4n-1)/2

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Solution for (n+3)/5=(-4n-1)/2 equation: 



(n+3)/5=(-4n-1)/2

We move all terms to the left:

(n+3)/5-((-4n-1)/2)=0

We calculate fractions


n/()+(-((-4n-1)*5)/()=0



We calculate terms in parentheses: +(-((-4n-1)*5)/(), so:

-((-4n-1)*5)/(

We multiply all the terms by the denominator


-((-4n-1)*5)



We calculate terms in parentheses: -((-4n-1)*5), so:

(-4n-1)*5

We multiply parentheses

-20n-5

Back to the equation:

-(-20n-5)



We get rid of parentheses

20n+5

Back to the equation:

+(20n+5)



We get rid of parentheses

n/()+20n+5=0

We multiply all the terms by the denominator


n+20n*()+5*()=0

We add all the numbers together, and all the variables

n+20n*()=0

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