-4(v+1)=5v-4+2(3v+3)

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Solution for -4(v+1)=5v-4+2(3v+3) equation: 



-4(v+1)=5v-4+2(3v+3)

We move all terms to the left:

-4(v+1)-(5v-4+2(3v+3))=0

We multiply parentheses

-4v-(5v-4+2(3v+3))-4=0



We calculate terms in parentheses: -(5v-4+2(3v+3)), so:

5v-4+2(3v+3)

determiningTheFunctionDomain
5v+2(3v+3)-4

We multiply parentheses

5v+6v+6-4

We add all the numbers together, and all the variables

11v+2

Back to the equation:

-(11v+2)



We get rid of parentheses

-4v-11v-2-4=0

We add all the numbers together, and all the variables

-15v-6=0

We move all terms containing v to the left, all other terms to the right

-15v=6

v=6/-15

v=-2/5

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