(2/3x+10)=(15)

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Solution for (2/3x+10)=(15) equation: 



(2/3x+10)=(15)

We move all terms to the left:

(2/3x+10)-((15))=0



Domain of the equation: 3x+10)!=0

x∈R



determiningTheFunctionDomain
(2/3x+10)-15=0

We get rid of parentheses

2/3x+10-15=0

We multiply all the terms by the denominator


10*3x-15*3x+2=0

Wy multiply elements

30x-45x+2=0

We add all the numbers together, and all the variables

-15x+2=0

We move all terms containing x to the left, all other terms to the right

-15x=-2

x=-2/-15

x=2/15

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