-4(t-7)-(t-3)=3

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Solution for -4(t-7)-(t-3)=3 equation: 



-4(t-7)-(t-3)=3

We move all terms to the left:

-4(t-7)-(t-3)-(3)=0

We multiply parentheses

-4t-(t-3)+28-3=0

We get rid of parentheses

-4t-t+3+28-3=0

We add all the numbers together, and all the variables

-5t+28=0

We move all terms containing t to the left, all other terms to the right

-5t=-28

t=-28/-5

t=5+3/5

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