8(2-y)+2y=32

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Solution for 8(2-y)+2y=32 equation: 



8(2-y)+2y=32

We move all terms to the left:

8(2-y)+2y-(32)=0

We add all the numbers together, and all the variables

8(-1y+2)+2y-32=0

We add all the numbers together, and all the variables

2y+8(-1y+2)-32=0

We multiply parentheses

2y-8y+16-32=0

We add all the numbers together, and all the variables

-6y-16=0

We move all terms containing y to the left, all other terms to the right

-6y=16

y=16/-6

y=-2+2/3

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