-4(t-4)-(t+3)=1

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Solution for -4(t-4)-(t+3)=1 equation:


Simplifying
-4(t + -4) + -1(t + 3) = 1

Reorder the terms:
-4(-4 + t) + -1(t + 3) = 1
(-4 * -4 + t * -4) + -1(t + 3) = 1
(16 + -4t) + -1(t + 3) = 1

Reorder the terms:
16 + -4t + -1(3 + t) = 1
16 + -4t + (3 * -1 + t * -1) = 1
16 + -4t + (-3 + -1t) = 1

Reorder the terms:
16 + -3 + -4t + -1t = 1

Combine like terms: 16 + -3 = 13
13 + -4t + -1t = 1

Combine like terms: -4t + -1t = -5t
13 + -5t = 1

Solving
13 + -5t = 1

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + -5t = 1 + -13

Combine like terms: 13 + -13 = 0
0 + -5t = 1 + -13
-5t = 1 + -13

Combine like terms: 1 + -13 = -12
-5t = -12

Divide each side by '-5'.
t = 2.4

Simplifying
t = 2.4

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