5(3z-1)-3(z+2)=4(z+1)

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Solution for 5(3z-1)-3(z+2)=4(z+1) equation:


Simplifying
5(3z + -1) + -3(z + 2) = 4(z + 1)

Reorder the terms:
5(-1 + 3z) + -3(z + 2) = 4(z + 1)
(-1 * 5 + 3z * 5) + -3(z + 2) = 4(z + 1)
(-5 + 15z) + -3(z + 2) = 4(z + 1)

Reorder the terms:
-5 + 15z + -3(2 + z) = 4(z + 1)
-5 + 15z + (2 * -3 + z * -3) = 4(z + 1)
-5 + 15z + (-6 + -3z) = 4(z + 1)

Reorder the terms:
-5 + -6 + 15z + -3z = 4(z + 1)

Combine like terms: -5 + -6 = -11
-11 + 15z + -3z = 4(z + 1)

Combine like terms: 15z + -3z = 12z
-11 + 12z = 4(z + 1)

Reorder the terms:
-11 + 12z = 4(1 + z)
-11 + 12z = (1 * 4 + z * 4)
-11 + 12z = (4 + 4z)

Solving
-11 + 12z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-11 + 12z + -4z = 4 + 4z + -4z

Combine like terms: 12z + -4z = 8z
-11 + 8z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-11 + 8z = 4 + 0
-11 + 8z = 4

Add '11' to each side of the equation.
-11 + 11 + 8z = 4 + 11

Combine like terms: -11 + 11 = 0
0 + 8z = 4 + 11
8z = 4 + 11

Combine like terms: 4 + 11 = 15
8z = 15

Divide each side by '8'.
z = 1.875

Simplifying
z = 1.875

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