-4(a+3)+1/2(6a-12)=-32

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Solution for -4(a+3)+1/2(6a-12)=-32 equation: 



-4(a+3)+1/2(6a-12)=-32

We move all terms to the left:

-4(a+3)+1/2(6a-12)-(-32)=0



Domain of the equation: 2(6a-12)!=0

a∈R



We add all the numbers together, and all the variables

-4(a+3)+1/2(6a-12)+32=0

We multiply parentheses

-4a+1/2(6a-12)-12+32=0

We multiply all the terms by the denominator


-4a*2(6a-12)-12*2(6a-12)+32*2(6a-12)+1=0

Wy multiply elements

-8a^2(6-24a(6+64a(6+1=0

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