1+4n=-1-2(3-n)

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Solution for 1+4n=-1-2(3-n) equation: 



1+4n=-1-2(3-n)

We move all terms to the left:

1+4n-(-1-2(3-n))=0

We add all the numbers together, and all the variables

4n-(-1-2(-1n+3))+1=0



We calculate terms in parentheses: -(-1-2(-1n+3)), so:

-1-2(-1n+3)

determiningTheFunctionDomain
-2(-1n+3)-1

We multiply parentheses

2n-6-1

We add all the numbers together, and all the variables

2n-7

Back to the equation:

-(2n-7)



We get rid of parentheses

4n-2n+7+1=0

We add all the numbers together, and all the variables

2n+8=0

We move all terms containing n to the left, all other terms to the right

2n=-8

n=-8/2

n=-4

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