-4(5d-3)+5(d+3)=20

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Solution for -4(5d-3)+5(d+3)=20 equation: 



-4(5d-3)+5(d+3)=20

We move all terms to the left:

-4(5d-3)+5(d+3)-(20)=0

We multiply parentheses

-20d+5d+12+15-20=0

We add all the numbers together, and all the variables

-15d+7=0

We move all terms containing d to the left, all other terms to the right

-15d=-7

d=-7/-15

d=7/15

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