-8(2x-3)+20x=48

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Solution for -8(2x-3)+20x=48 equation: 



-8(2x-3)+20x=48

We move all terms to the left:

-8(2x-3)+20x-(48)=0

We add all the numbers together, and all the variables

20x-8(2x-3)-48=0

We multiply parentheses

20x-16x+24-48=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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