-4(4y-1)+5y=9+2(2y-1)

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Solution for -4(4y-1)+5y=9+2(2y-1) equation: 



-4(4y-1)+5y=9+2(2y-1)

We move all terms to the left:

-4(4y-1)+5y-(9+2(2y-1))=0

We add all the numbers together, and all the variables

5y-4(4y-1)-(9+2(2y-1))=0

We multiply parentheses

5y-16y-(9+2(2y-1))+4=0



We calculate terms in parentheses: -(9+2(2y-1)), so:

9+2(2y-1)

determiningTheFunctionDomain
2(2y-1)+9

We multiply parentheses

4y-2+9

We add all the numbers together, and all the variables

4y+7

Back to the equation:

-(4y+7)



We add all the numbers together, and all the variables

-11y-(4y+7)+4=0

We get rid of parentheses

-11y-4y-7+4=0

We add all the numbers together, and all the variables

-15y-3=0

We move all terms containing y to the left, all other terms to the right

-15y=3

y=3/-15

y=-1/5

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