-4(4v-2)+6v=2(v+7)

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Solution for -4(4v-2)+6v=2(v+7) equation: 



-4(4v-2)+6v=2(v+7)

We move all terms to the left:

-4(4v-2)+6v-(2(v+7))=0

We add all the numbers together, and all the variables

6v-4(4v-2)-(2(v+7))=0

We multiply parentheses

6v-16v-(2(v+7))+8=0



We calculate terms in parentheses: -(2(v+7)), so:

2(v+7)

We multiply parentheses

2v+14

Back to the equation:

-(2v+14)



We add all the numbers together, and all the variables

-10v-(2v+14)+8=0

We get rid of parentheses

-10v-2v-14+8=0

We add all the numbers together, and all the variables

-12v-6=0

We move all terms containing v to the left, all other terms to the right

-12v=6

v=6/-12

v=-1/2

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