3y-7+2(3y+4)=-5(y+1)

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Solution for 3y-7+2(3y+4)=-5(y+1) equation: 



3y-7+2(3y+4)=-5(y+1)

We move all terms to the left:

3y-7+2(3y+4)-(-5(y+1))=0

We multiply parentheses

3y+6y-(-5(y+1))+8-7=0



We calculate terms in parentheses: -(-5(y+1)), so:

-5(y+1)

We multiply parentheses

-5y-5

Back to the equation:

-(-5y-5)



We add all the numbers together, and all the variables

9y-(-5y-5)+1=0

We get rid of parentheses

9y+5y+5+1=0

We add all the numbers together, and all the variables

14y+6=0

We move all terms containing y to the left, all other terms to the right

14y=-6

y=-6/14

y=-3/7

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