-4(4-x)=-3(2x-5)+3x

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Solution for -4(4-x)=-3(2x-5)+3x equation: 



-4(4-x)=-3(2x-5)+3x

We move all terms to the left:

-4(4-x)-(-3(2x-5)+3x)=0

We add all the numbers together, and all the variables

-4(-1x+4)-(-3(2x-5)+3x)=0

We multiply parentheses

4x-(-3(2x-5)+3x)-16=0



We calculate terms in parentheses: -(-3(2x-5)+3x), so:

-3(2x-5)+3x

We add all the numbers together, and all the variables

3x-3(2x-5)

We multiply parentheses

3x-6x+15

We add all the numbers together, and all the variables

-3x+15

Back to the equation:

-(-3x+15)



We get rid of parentheses

4x+3x-15-16=0

We add all the numbers together, and all the variables

7x-31=0

We move all terms containing x to the left, all other terms to the right

7x=31

x=31/7

x=4+3/7

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