9(4-x)-4x=2(x-3)+10

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Solution for 9(4-x)-4x=2(x-3)+10 equation: 



9(4-x)-4x=2(x-3)+10

We move all terms to the left:

9(4-x)-4x-(2(x-3)+10)=0

We add all the numbers together, and all the variables

9(-1x+4)-4x-(2(x-3)+10)=0

We add all the numbers together, and all the variables

-4x+9(-1x+4)-(2(x-3)+10)=0

We multiply parentheses

-4x-9x-(2(x-3)+10)+36=0



We calculate terms in parentheses: -(2(x-3)+10), so:

2(x-3)+10

We multiply parentheses

2x-6+10

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

-13x-(2x+4)+36=0

We get rid of parentheses

-13x-2x-4+36=0

We add all the numbers together, and all the variables

-15x+32=0

We move all terms containing x to the left, all other terms to the right

-15x=-32

x=-32/-15

x=2+2/15

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