-4(3y-5)+4y=4(y+7)

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Solution for -4(3y-5)+4y=4(y+7) equation: 



-4(3y-5)+4y=4(y+7)

We move all terms to the left:

-4(3y-5)+4y-(4(y+7))=0

We add all the numbers together, and all the variables

4y-4(3y-5)-(4(y+7))=0

We multiply parentheses

4y-12y-(4(y+7))+20=0



We calculate terms in parentheses: -(4(y+7)), so:

4(y+7)

We multiply parentheses

4y+28

Back to the equation:

-(4y+28)



We add all the numbers together, and all the variables

-8y-(4y+28)+20=0

We get rid of parentheses

-8y-4y-28+20=0

We add all the numbers together, and all the variables

-12y-8=0

We move all terms containing y to the left, all other terms to the right

-12y=8

y=8/-12

y=-2/3

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