8x-3/4x+5=0

Solution for 8x-3/4x+5=0 equation:

8x-3/4x+5=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We multiply all the terms by the denominator


8x*4x+5*4x-3=0

Wy multiply elements

32x^2+20x-3=0

a = 32; b = 20; c = -3;
Δ = b2-4ac
Δ = 202-4·32·(-3)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*32}=\frac{-48}{64}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*32}=\frac{8}{64}
=1/8
$