-4(3y-3)-y=-2(y-2)

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Solution for -4(3y-3)-y=-2(y-2) equation: 



-4(3y-3)-y=-2(y-2)

We move all terms to the left:

-4(3y-3)-y-(-2(y-2))=0

We add all the numbers together, and all the variables

-1y-4(3y-3)-(-2(y-2))=0

We multiply parentheses

-1y-12y-(-2(y-2))+12=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We add all the numbers together, and all the variables

-13y-(-2y+4)+12=0

We get rid of parentheses

-13y+2y-4+12=0

We add all the numbers together, and all the variables

-11y+8=0

We move all terms containing y to the left, all other terms to the right

-11y=-8

y=-8/-11

y=8/11

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