3(2x-1)-5(x-3)+6(3x-4)=24

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Solution for 3(2x-1)-5(x-3)+6(3x-4)=24 equation:



3(2x-1)-5(x-3)+6(3x-4)=24
We move all terms to the left:
3(2x-1)-5(x-3)+6(3x-4)-(24)=0
We multiply parentheses
6x-5x+18x-3+15-24-24=0
We add all the numbers together, and all the variables
19x-36=0
We move all terms containing x to the left, all other terms to the right
19x=36
x=36/19
x=1+17/19

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