-4(3c+1)=3c=3(2c+6)-5

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Solution for -4(3c+1)=3c=3(2c+6)-5 equation: 



-4(3c+1)=3c=3(2c+6)-5

We move all terms to the left:

-4(3c+1)-(3c)=0

We add all the numbers together, and all the variables

-3c-4(3c+1)=0

We multiply parentheses

-3c-12c-4=0

We add all the numbers together, and all the variables

-15c-4=0

We move all terms containing c to the left, all other terms to the right

-15c=4

c=4/-15

c=-4/15

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