4(2c-1)+6=14=6(3c-2)

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Solution for 4(2c-1)+6=14=6(3c-2) equation: 



4(2c-1)+6=14=6(3c-2)

We move all terms to the left:

4(2c-1)+6-(14)=0

We add all the numbers together, and all the variables

4(2c-1)-8=0

We multiply parentheses

8c-4-8=0

We add all the numbers together, and all the variables

8c-12=0

We move all terms containing c to the left, all other terms to the right

8c=12

c=12/8

c=1+1/2

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