-4(2x-3)=20+2x+28

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Solution for -4(2x-3)=20+2x+28 equation: 



-4(2x-3)=20+2x+28

We move all terms to the left:

-4(2x-3)-(20+2x+28)=0

We add all the numbers together, and all the variables

-4(2x-3)-(2x+48)=0

We multiply parentheses

-8x-(2x+48)+12=0

We get rid of parentheses

-8x-2x-48+12=0

We add all the numbers together, and all the variables

-10x-36=0

We move all terms containing x to the left, all other terms to the right

-10x=36

x=36/-10

x=-3+3/5

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