-4(2x-3)+2(x-2)=8

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Solution for -4(2x-3)+2(x-2)=8 equation:



-4(2x-3)+2(x-2)=8
We move all terms to the left:
-4(2x-3)+2(x-2)-(8)=0
We multiply parentheses
-8x+2x+12-4-8=0
We add all the numbers together, and all the variables
-6x=0
x=0/-6
x=0

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