3m=2(m-5)+15

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Solution for 3m=2(m-5)+15 equation: 



3m=2(m-5)+15

We move all terms to the left:

3m-(2(m-5)+15)=0



We calculate terms in parentheses: -(2(m-5)+15), so:

2(m-5)+15

We multiply parentheses

2m-10+15

We add all the numbers together, and all the variables

2m+5

Back to the equation:

-(2m+5)



We get rid of parentheses

3m-2m-5=0

We add all the numbers together, and all the variables

m-5=0

We move all terms containing m to the left, all other terms to the right

m=5

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