-4(2v-7)+2v=6(v+4)

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Solution for -4(2v-7)+2v=6(v+4) equation: 



-4(2v-7)+2v=6(v+4)

We move all terms to the left:

-4(2v-7)+2v-(6(v+4))=0

We add all the numbers together, and all the variables

2v-4(2v-7)-(6(v+4))=0

We multiply parentheses

2v-8v-(6(v+4))+28=0



We calculate terms in parentheses: -(6(v+4)), so:

6(v+4)

We multiply parentheses

6v+24

Back to the equation:

-(6v+24)



We add all the numbers together, and all the variables

-6v-(6v+24)+28=0

We get rid of parentheses

-6v-6v-24+28=0

We add all the numbers together, and all the variables

-12v+4=0

We move all terms containing v to the left, all other terms to the right

-12v=-4

v=-4/-12

v=1/3

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