1/3x-2/3=4x-3(x-1)+29/3

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Solution for 1/3x-2/3=4x-3(x-1)+29/3 equation: 



1/3x-2/3=4x-3(x-1)+29/3

We move all terms to the left:

1/3x-2/3-(4x-3(x-1)+29/3)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We calculate fractions


()/27x^2+(-(4x-3(x-1)+29*3x)/27x^2=0

We multiply all the terms by the denominator


(-(4x-3(x-1)+29*3x)+()=0



We calculate terms in parentheses: +(-(4x-3(x-1)+29*3x)+(), so:

-(4x-3(x-1)+29*3x)+(

We add all the numbers together, and all the variables

-(4x-3(x-1)+29*3x)



We calculate terms in parentheses: -(4x-3(x-1)+29*3x), so:

4x-3(x-1)+29*3x

We multiply parentheses

4x-3x+29*3x+3

Wy multiply elements

4x-3x+87x+3

We add all the numbers together, and all the variables

88x+3

Back to the equation:

-(88x+3)



We get rid of parentheses

-88x-3

Back to the equation:

+(-88x-3)



We get rid of parentheses

-88x-3=0

We move all terms containing x to the left, all other terms to the right

-88x=3

x=3/-88

x=-3/88

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