-4(2v-2)+3v=3(v+4)

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Solution for -4(2v-2)+3v=3(v+4) equation: 



-4(2v-2)+3v=3(v+4)

We move all terms to the left:

-4(2v-2)+3v-(3(v+4))=0

We add all the numbers together, and all the variables

3v-4(2v-2)-(3(v+4))=0

We multiply parentheses

3v-8v-(3(v+4))+8=0



We calculate terms in parentheses: -(3(v+4)), so:

3(v+4)

We multiply parentheses

3v+12

Back to the equation:

-(3v+12)



We add all the numbers together, and all the variables

-5v-(3v+12)+8=0

We get rid of parentheses

-5v-3v-12+8=0

We add all the numbers together, and all the variables

-8v-4=0

We move all terms containing v to the left, all other terms to the right

-8v=4

v=4/-8

v=-1/2

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