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(3x+12)(5x-18)=180
We move all terms to the left:
(3x+12)(5x-18)-(180)=0
We multiply parentheses ..
(+15x^2-54x+60x-216)-180=0
We get rid of parentheses
15x^2-54x+60x-216-180=0
We add all the numbers together, and all the variables
15x^2+6x-396=0
a = 15; b = 6; c = -396;
Δ = b2-4ac
Δ = 62-4·15·(-396)
Δ = 23796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23796}=\sqrt{36*661}=\sqrt{36}*\sqrt{661}=6\sqrt{661}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{661}}{2*15}=\frac{-6-6\sqrt{661}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{661}}{2*15}=\frac{-6+6\sqrt{661}}{30} $
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