-4(1-3k)-3=7(k-3)+6k

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Solution for -4(1-3k)-3=7(k-3)+6k equation:



-4(1-3k)-3=7(k-3)+6k
We move all terms to the left:
-4(1-3k)-3-(7(k-3)+6k)=0
We add all the numbers together, and all the variables
-4(-3k+1)-(7(k-3)+6k)-3=0
We multiply parentheses
12k-(7(k-3)+6k)-4-3=0
We calculate terms in parentheses: -(7(k-3)+6k), so:
7(k-3)+6k
We add all the numbers together, and all the variables
6k+7(k-3)
We multiply parentheses
6k+7k-21
We add all the numbers together, and all the variables
13k-21
Back to the equation:
-(13k-21)
We add all the numbers together, and all the variables
12k-(13k-21)-7=0
We get rid of parentheses
12k-13k+21-7=0
We add all the numbers together, and all the variables
-1k+14=0
We move all terms containing k to the left, all other terms to the right
-k=-14
k=-14/-1
k=+14

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