3(x+2)=3(3+2x)

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Solution for 3(x+2)=3(3+2x) equation: 



3(x+2)=3(3+2x)

We move all terms to the left:

3(x+2)-(3(3+2x))=0

We add all the numbers together, and all the variables

3(x+2)-(3(2x+3))=0

We multiply parentheses

3x-(3(2x+3))+6=0



We calculate terms in parentheses: -(3(2x+3)), so:

3(2x+3)

We multiply parentheses

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

3x-6x-9+6=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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