-4(-7y+1)-8y=2(y-2)-3

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Solution for -4(-7y+1)-8y=2(y-2)-3 equation: 



-4(-7y+1)-8y=2(y-2)-3

We move all terms to the left:

-4(-7y+1)-8y-(2(y-2)-3)=0

We add all the numbers together, and all the variables

-8y-4(-7y+1)-(2(y-2)-3)=0

We multiply parentheses

-8y+28y-(2(y-2)-3)-4=0



We calculate terms in parentheses: -(2(y-2)-3), so:

2(y-2)-3

We multiply parentheses

2y-4-3

We add all the numbers together, and all the variables

2y-7

Back to the equation:

-(2y-7)



We add all the numbers together, and all the variables

20y-(2y-7)-4=0

We get rid of parentheses

20y-2y+7-4=0

We add all the numbers together, and all the variables

18y+3=0

We move all terms containing y to the left, all other terms to the right

18y=-3

y=-3/18

y=-1/6

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