(8x+9)(8x+9)=(8x+9)

Solution for (8x+9)(8x+9)=(8x+9) equation:

(8x+9)(8x+9)=(8x+9)

We move all terms to the left:

(8x+9)(8x+9)-((8x+9))=0

We multiply parentheses ..

(+64x^2+72x+72x+81)-((8x+9))=0


We calculate terms in parentheses: -((8x+9)), so:

(8x+9)

We get rid of parentheses

8x+9

Back to the equation:

-(8x+9)


We get rid of parentheses

64x^2+72x+72x-8x+81-9=0

We add all the numbers together, and all the variables

64x^2+136x+72=0

a = 64; b = 136; c = +72;
Δ = b2-4ac
Δ = 1362-4·64·72
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(136)-8}{2*64}=\frac{-144}{128}
=-1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(136)+8}{2*64}=\frac{-128}{128}
=-1
$