-4(-4y+4)-2y=5(y-1)-5

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Solution for -4(-4y+4)-2y=5(y-1)-5 equation: 



-4(-4y+4)-2y=5(y-1)-5

We move all terms to the left:

-4(-4y+4)-2y-(5(y-1)-5)=0

We add all the numbers together, and all the variables

-2y-4(-4y+4)-(5(y-1)-5)=0

We multiply parentheses

-2y+16y-(5(y-1)-5)-16=0



We calculate terms in parentheses: -(5(y-1)-5), so:

5(y-1)-5

We multiply parentheses

5y-5-5

We add all the numbers together, and all the variables

5y-10

Back to the equation:

-(5y-10)



We add all the numbers together, and all the variables

14y-(5y-10)-16=0

We get rid of parentheses

14y-5y+10-16=0

We add all the numbers together, and all the variables

9y-6=0

We move all terms containing y to the left, all other terms to the right

9y=6

y=6/9

y=2/3

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