100(1-x)(1+x)=100

Solution for 100(1-x)(1+x)=100 equation:

100(1-x)(1+x)=100

We move all terms to the left:

100(1-x)(1+x)-(100)=0

We add all the numbers together, and all the variables

100(-1x+1)(x+1)-100=0

We multiply parentheses ..

100(-1x^2-1x+x+1)-100=0

We multiply parentheses

-100x^2-100x+100x+100-100=0

We add all the numbers together, and all the variables

-100x^2=0

a = -100; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-100)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-200}=0$