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-3x+4(2x+2)=2(3x-3)+11
We move all terms to the left:
-3x+4(2x+2)-(2(3x-3)+11)=0
We multiply parentheses
-3x+8x-(2(3x-3)+11)+8=0
We calculate terms in parentheses: -(2(3x-3)+11), so:We add all the numbers together, and all the variables
2(3x-3)+11
We multiply parentheses
6x-6+11
We add all the numbers together, and all the variables
6x+5
Back to the equation:
-(6x+5)
5x-(6x+5)+8=0
We get rid of parentheses
5x-6x-5+8=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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