(2/3)m+(5/4)m-m=(11/12)m

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Solution for (2/3)m+(5/4)m-m=(11/12)m equation: 



(2/3)m+(5/4)m-m=(11/12)m

We move all terms to the left:

(2/3)m+(5/4)m-m-((11/12)m)=0



Domain of the equation: 3)m!=0

m!=0/1

m!=0

m∈R





Domain of the equation: 4)m!=0

m!=0/1

m!=0

m∈R





Domain of the equation: 12)m)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(+2/3)m+(+5/4)m-m-((+11/12)m)=0

We add all the numbers together, and all the variables

-1m+(+2/3)m+(+5/4)m-((+11/12)m)=0

We multiply parentheses

2m^2+5m^2-1m-((+11/12)m)=0

We multiply all the terms by the denominator


2m^2*12)m)+5m^2*12)m)-1m*12)m)-((+11=0

Wy multiply elements

3456m^5=0

We do not support empression: m^5

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