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-3x(x+5)=2(x+5)
We move all terms to the left:
-3x(x+5)-(2(x+5))=0
We multiply parentheses
-3x^2-15x-(2(x+5))=0
We calculate terms in parentheses: -(2(x+5)), so:We get rid of parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
-3x^2-15x-2x-10=0
We add all the numbers together, and all the variables
-3x^2-17x-10=0
a = -3; b = -17; c = -10;
Δ = b2-4ac
Δ = -172-4·(-3)·(-10)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-13}{2*-3}=\frac{4}{-6} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+13}{2*-3}=\frac{30}{-6} =-5 $
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