4a-3=2(a+1)+9a+3

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Solution for 4a-3=2(a+1)+9a+3 equation: 



4a-3=2(a+1)+9a+3

We move all terms to the left:

4a-3-(2(a+1)+9a+3)=0



We calculate terms in parentheses: -(2(a+1)+9a+3), so:

2(a+1)+9a+3

We add all the numbers together, and all the variables

9a+2(a+1)+3

We multiply parentheses

9a+2a+2+3

We add all the numbers together, and all the variables

11a+5

Back to the equation:

-(11a+5)



We get rid of parentheses

4a-11a-5-3=0

We add all the numbers together, and all the variables

-7a-8=0

We move all terms containing a to the left, all other terms to the right

-7a=8

a=8/-7

a=-1+1/7

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